If `(asectheta, btantheta)` and `(asecphi, btanphi)` be two coordinate of the ends of a focal chord passing through `(ae,0)` of `x^2/a^2-y^2/b^2=1` then `tan(theta/2)tan(phi/2)` equals to

If (asectheta;btantheta) and (asecphi; btanphi) are the ends of the focal chord of x^2/a^2-y^2/b^2=1 then prove that tan(x/a)tan(phi/2)=(1-e)/(1+e)

The locus of mid-points of a focal chord of the ellipse x^2/a^2+y^2/b^2=1

2 tan^(-1) (-2) is equal to

1 + tan^2 theta = ?

Let P(a sectheta, btantheta) and Q(aseccphi , btanphi) (where theta+phi=pi/2 be two points on the hyperbola x^2/a^2-y^2/b^2=1 If (h, k) is the point of intersection of the normals at P and Q then k is equal to (A) (a^2+b^2)/a (B) -((a^2+b^2)/a) (C) (a^2+b^2)/b (D) -((a^2+b^2)/b)

If 2sec 2theta=tan phi+cotphi , then one of the values of theta+phi is

If (a ,b) is the midpoint of a chord passing through the vertex of the parabola y^2=4x, then prove that 2a=b^2

The coordinates of the ends of a focal chord of the parabola y^2=4a x are (x_1, y_1) and (x_2, y_2) . Then find the value of x_1x_2+y_1y_2 .

If tan 3 theta + tan theta =2 tan 2 theta , then theta is equal to (n in Z)