If the foci of the ellipse ` x^(2)/16 + y^(2)/b^(2) =1` and the hyperbola ` x^(2)/144 - y^(2)/81 = 1/25` coincide then ` b^(2)` is

The foci of the ellipse 25(x + 1)^2 + 9(y + 2)^2 = 225

The ellipse (x^(2))/(25)+(y^(2))/(16)=1 and the hyperbola (x^(2))/(25)-(y^(2))/(16) =1 have in common

The auxiliary circle of the ellipse x^(2)/25 + y^(2)/16 = 1

The vertices of the ellipse 16x^(2) + 25y^(2) = 400 are …………

The eccentricity of the ellipse 16x^2 + 25y^2 = 400 is

The vertices of the hyperbola 9x^2 - 16y^2 = 144

For the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2)) =1 and (x^(2))/(b^(2))+(y^(2))/(a^(2)) =1

If the midpoint of the chord of the ellipse x^2/16+y^2/25=1 is (0,3)

The foci a hyperbola coincides with the foci of the ellispe x^(2)/25 + y^(2)/9 = 1 . Find the equation of the hyperbola if its eccentricity is 2.