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If the normal at p(theta) on the hyperbo...

If the normal at `p(theta)` on the hyperbola `(x^(2))/(a^(2))-(y^(2))/(b^(2))=1` meets the transverse axis at G, then prove that `AG*A'G=a^(2)(e^(4)sec^(2)theta-1),` where A and A' are the vertices of the hyperbola.

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