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An ellipse intersects the hyperbola 2x^2...

An ellipse intersects the hyperbola `2x^2-2y^2 =1` orthogonally. The eccentricity of the ellipse is reciprocal to that of the hyperbola. If the axes of the ellipse are along the coordinate axes, then (a) equation of ellipse is `x^2+ 2y^2 =2`(b) the foci of ellipse are `(+-1, 0)` (c) equation of ellipse is `(x^2 +2y=4)` (d) the foci of ellipse are `(+-2, 0)`

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