The point of intersection of the lines (x-5)/3=(y-7)/(-1)=(z+2)/1 and (x+3)/(-36)=(y-3)/2=(z-6)/4 is (A) (21 ,5/3,(10)/3) (B) (2,10 ,4) (C) (-3,3,6) (D) (5,7,-2)

Find the point of intersection of the lines (x-1)/(3)=(y-1)/(-1) = z+2’and (x-4)/(2)=y=(z+1)/(3) .

Find the point of intersection of the lines (x-1)/(2)=(y-2)/(3)=(z-3)/(4) and (x-4)/(5)=(y-1)/(2)=z .

Find the point of intersection of the lines (x - 1)/(2) = (y - 2)/(3) = (z - 3)/(4) and (x - 4)/(5) = (y - 1)/(2) = z.

The shortest distance between the lines (x-3)/3=(y-8)/(-1)=(z-3)/1a n d(x+3)/(-3)=(y+7)/2=(z-6)/4 is

Show that the disease of the point of intersection of the line (x-2)/3=(y+1)/4=(z-2)/12 and the plane (x-y+z=5) from the point (-1,-5,-10) is 13 units.

Column I, Column II Image of the point (3,5,7) in the plane 2x+y+z=-18 is, p. (-1,1,-1) The point of intersection of the line (x-2)/(-3)=(y-1)/(-2)=(z-3)/2 and the plane 2x+y-z=3 is, q. (-21 ,-7,-5) The foot of the perpendicular from the point (1,1,2) to the plane 2x-2y+4z+5=0 is, r. (5/2,2/3,8/3) The intersection point of the lines (x-1)/2=(y-2)/3=(z-3)/4a n d(x-4)/5=(y-1)/2=z is, s. (-1/(12),(25)/(12),(-2)/(12))

The equation of the plane which passes through the point of intersection of lines ""(x-1)/3=(y-2)/1=(z-3)/2"","and"(x-3)/1=(y-1)/2=(z-2)/3 and at greatest distance from point (0,0,0) is a. 4x+3y+5z=25 b. 4x+3y=5z=50 c. 3x+4y+5z=49 d. x+7y-5z=2

The shortest distance between the lines (x-3)/3=(y-8)/(-1)=(z-3)/1a n d(x+3)/(-3)=(y+7)/2=(z-6)/4 is a. sqrt(30) b. 2sqrt(30) c. 5sqrt(30) d. 3sqrt(30)

Equation of a line in the plane pi =2x-y+z-4=0 which is perpendicular to the line l whose equation is (x-2)/1=(y-2)/(-1)=(z-3)/(-2) and which passes through the point of intersection of l and pi is (A) (x-2)/1=(y-1)/5=(z-1)/(-1) (B) (x-1)/3=(y-3)/5=(z-5)/(-1) (C) (x+2)/2=(y+1)/(-1)=(z+1)/1 (D) (x-2)/2=(y-1)/(-1)=(z-1)/1