`(f(x y))^2=x(f(y))^2:f(2)=6` A function f: R+ ? R+ defined as Then `f(100) =?`

The function f:R->[-1/2,1/2] defined as f(x)=x/(1+x^2) is

Let f be a function defined from F^(+)rarrR^(+). If (f(xy))^(2)=x(f(y))^(2) for all positive numbers x and y, If f(2)=6, find f(50) =?

Let f(x) be real valued and differentiable function on R such that f(x+y)=(f(x)+f(y))/(1-f(x)dotf(y)) f(x) is Odd function Even function Odd and even function simultaneously Neither even nor odd

If a function f: R ->R be such that f(x-f(y)) = f(f(y) )+xf(y)+f(x) -1 AA x , y in R then f(2)=

If f(x+y+1)={sqrt(f(x))+sqrt(f(y))}^2 and f(0)=1AAx ,y in R ,determine f(n),n in Ndot

If for a function f : R to R f (x +y ) =F(x ) + f(y) for all x and y then f(0) is

Consider a differentiable f:R to R for which f(1)=2 and f(x+y)=2^(x)f(y)+4^(y)f(x) AA x , y in R. The number of solutions of f(x)=2 is

f: RrarrR ,f(x^2+x+3)+2f(x^2-3x+5)=6x^2-10 x+17AAx in R , then find the function f(x)dot

Let the function f: R rarr R be defined as f(x)=min .(x+2,4-2 x, 1+4 x ). The maximum vatue of f(x) is equal to

A real valued function f (x) satisfies the functional equation f (x-y)= f(x) f(y) - f(a-x) f(a +y) where a is a given constant and f (0) =1, f(2a -x) is equal to