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If t(1+x^2)=x and x^2+t^2=y, then at x=2...

If `t(1+x^2)=x and x^2+t^2=y,` then at `x=2` the value of `(d y)/(d x)` is equal to Option 1. 24/5 Option 2: 101/125 Option 3: 488/155 Option 4: 358/125

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