The straight lines represented by the equation `135 x^2-136 x y+33 y^2=0` are equally inclined to the line (a)`x-2y=7` (b) x+2y=7 (c)`x-2y=4` (d) `3x+2y=4`

Options

A. `x-2y=7`
B. `x+2y=7`
C. `x-2y=4`
D. `3x+2y=4`

Answer

2

Explanation

The given pair of lines is
`135x^(2)-136xy+33y^(2)=0` (1)
the equation of bisectors of angles between the pairs of lines (1) is
`(x^(2)-y^(2))/(a-b)=(xy)/(h)or(x^(2)-y^(2))/(135-33)=(xy)/(-68)`
or `2x^(2)+3xy-2y^(2)=0`(2)
or `(x+2)(2x-y)=0`
One of the bisectors is `x+2y=0` which is parallel to the line `x+2y=7`.
Hence , the line `x+2y=7` is equally inclined to the given lines.