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Draw the graph of y=sin^(-1)(cosx)....

Draw the graph of `y=sin^(-1)(cosx)`.

Text Solution

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We have `y=f(x)=sin(cosx)=(pi)/(2)-cos^(-1)(cosx)`
To draw the graph of `y=f(x)`, we first draw the graph of `y=cos^(-1)(cosx)`, then flip the graph over the x-axis to get the graph of `y=-cos^(-1)(cosx)` and then shift the graph by
`'pi/2'` units upward vertically to get the graph of `y=(pi)/(2)-cos^(-1)(cosx)`. The grapha of `y=cos^(-1)(cosx)` is as follows.

The graph of `y=-cos^(-1)(cosx)`
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