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Find the angel between the planes 2x+...

Find the angel between the planes `2x+y-2x+3=0a n d vec rdot(6 hat i+3 hat j+2 hat k)=5.`

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Normals along the given planes are `2hati+hatj-2hatk and 6hati+3hatj+2hatk`.
Then angle between planes, `theta = cos^(-1)=((2hati+hatj-2hatk)*(6hati+3hatj+2hatk))/(sqrt((2)^(2)+(1)^(2)+(-2)^(2))sqrt((6)^(2)+(3)^(2)+(2)^(2)))=cos^(-1)""(11)/(12)`
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