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If the lines (x-1)/(-3) =(y-2)/(2k) =(z-...

If the lines `(x-1)/(-3) =(y-2)/(2k) =(z-3)/2` and `(x-1)/(3k)=(y-1)/1=(z-6)/(-5)` are perpendicular , find the value of k .

Text Solution

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The lines are perpendicular if `a_(1)a_(2)+b_(1)b_(2)+c_(1)c_(2)=0`.
Hence, `-3(3k)+2k(1)+2(-5)=0 or k=-(10)/(7)`.
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