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The equation of the line throgh the poin...

The equation of the line throgh the point `veca` parallel to the plane `vecr.vecn`=q and ` perpendicular to the line `vecr=vecb+tvecc` is (A) `vecr=veca+lamda (vecnxxvecc)` (B) `(vecr-veca)xx(vecnxxvecc)=0` (C) `vecr=vecb+lamda(vecnxxvecc)` (D) none of these

A

`vecr=veca+lamda(vecnxxvecc)`

B

`(vecr-veca)xx(vecnxxvecc)=0`

C

`vecr=vecb+lamda(vecnxxvecc)`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
a, d

Required line is parallel to `vecnxxvecc`
The equation of line is `vecr= veca+lamda(vecnxxvecc)`
or `" "(vecr-veca)=lamda(vecnxxvecc)`
`therefore" "(vecr-veca)xx(vecnxxvecc)=0`
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