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Two lines L1x=5, y/(3-alpha)=z/(-2)a n d...

Two lines `L_1x=5, y/(3-alpha)=z/(-2)a n dL_2: x=alphay/(-1)=z/(2-alpha)` are coplanar. Then `alpha` can take value (s) a. `1` b. `2` c. `3` d. `4`

A

1

B

2

C

3

D

4

Text Solution

Verified by Experts

The correct Answer is:
a, d
Lines `(x-5)/(0)= (y-0)/(3-alpha)=(z-0)/(-2) and (x-alpha)/(0)= (y)/(-1) = (z)/(2-alpha)` will be coplanar if shortest distance is zero. Thus,
`" "|{:(5-alpha,,0,,0),(0,,3-alpha,,-2),(0,,-1,,2-alpha):}|=0`
or `" "(5-alpha)(alpha^(2)-5alpha+4)=0, alpha=1, 4, 5`
or `" "alpha=1, 4`
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