Number of intergal values of x satisfying the inequality `(x^2+6x-7)/(|x+2||x+3|) lt 0 ` is

Answer

A

Explanation

We have `(x^2+6x-7)/(|x+2||x+3|) lt 0 `
Clearly ,` ne -2,-3`
Now `x^2+6x-7 lt 0 `
`rArr (x+7)(x-1) lt 0 `
`rArr in (-7,1)-{-3,-2}`
So ,intergers are {-6 ,-5 -4,-1,0}