If |x + 2| `le` 9 , then x belongs to

Explanation

Draw the graph of `y= |x|` and lines `y=2 and y=5`.

Line `y=2` meets `y=|x|` at `A(2, 2) and B(-2, -2)`. From these points, drop perpendicular to the x-axis.
Line `y=5` meets `y= |x|` at `C(5, 5) and D(-5, -56)`. From these points, drop perpendiculars to the x-axis.
From the graph, required values of x are between P and Q and between R and S.
Therefore,
`" "x in [ -5, -2] uu [2, 5]`