Find the equations of the lines which pass through the origin and are inclined at an angle `tan^(-1)m` to the line `y=m x+cdot`

Answer

`y =0, y = (2mx)/(1-m^(2))`

Explanation

Angle between both the lines is
`"tan"^(-1)m+- "tan"^(-1)m = "tan"^(-1) (2m)/(1-m^(2)) or "tan"^(-1)0`
Therefore, the equations of the lines are
`y=0, y= (2mx)/(1-m^(2))`