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If the foot of perpendicular from the origin to a straight line is at the point (3,-4). Then the equation of the line is

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The correct Answer is:
3x-4y=25
Let P(3,-4) be the foot of the perpendicular from the origin O on the required line. Then the slope of OP is
`(-4-0)/(3-0) = -(4)/(3)`
Therefore, the slope of the required line is 3/4.
Hence, its equation is
`y+4 = (3)/(4)(x-3)`
or 3x-4y = 25
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CENGAGE-STRAIGHT LINES-Exercise 2.1
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