The equation of a straight line on which the length of perpendicular from the origin is four units and the line makes an angle of `120^0` with the x-axis is `xsqrt(3)+y+8=0` `xsqrt(3)-y=8` `xsqrt(3)-y=8` (d) `x-sqrt(3)y+8=0`

Options

A. `x sqrt(3) +y+8=0`
B. `x sqrt(3) -y =8`
C. `x sqrt(3) -y =8`
D. `x -sqrt(3)+8=0`

Answer

A

Explanation

Given that the slope is `-sqrt(3)`.
Therefore, the line is
`y=-sqrt(3) x +c`
`"or "sqrt(3) x +y =c`
`"Now, "|(c)/(2)| = 4 or c =+-8`
`"or "xsqrt(3) + y =+-8`