The locus of the centers of the circles `(x-1)^2+y^2=10a n dx^2+(y-2)^2=5` intersect is `pi/6` (b) `pi/4` (c) `pi/3` (d) `pi/2`

Options

A. `(pi)/(4)`
B. `(pi)/(2)`
C. `(pi)/(3)`
D. `(pi)/(6)`

Answer

B

Explanation

Clearly, distance between the parallel lines `(x)/(a)+(y)/(b) = 1 " and " (x)/(a) + (y)/(b) = 2 " is same as the distance between the parallel lines "(x)/(b)+(y)/(a) = 1 " and " (x)/(b)+(y)/(b) = 2`.
Therefore, quadrilateral is rhombus.