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A light ray coming along the line 3x+4y=...

A light ray coming along the line `3x+4y=5` gets reflected from the line `a x+b y=1` and goes along the line `5x-12 y=10.` Then, `a=(64)/(115), b=(112)/(15)` `a=(14)/(15), b=-8/(115)` `a=(64)/(115), b=-8/(115)` `a=(64)/(15), b=(14)/(15)`

A

`a=(64)/(115), b=(112)/(15)`

B

`a=(14)/(15), b=-(18)/(115)`

C

`a=(64)/(115), b=-(8)/(115)`

D

`a=(64)/(15), b=(14)/(15)`

Text Solution

Verified by Experts

The correct Answer is:
C

ax+by=1 will be one of the bisectors of the given line.
Bisectors of the given lines are
`(3x+4y-5)/(5)=+-((5x-12y-10)/(13))`
`rArr 64x-8y=115 " or " 14x+112y=15`
`therefore a=(64)/(115),b=-(8)/(115) "or a =(14)/(15), b =(112)/(15)`
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