The equation of the bisector of the acute angle between the lines `2x-y+4=0` and `x-2y=1` is `x-y+5=0` `x-y+1=0` `x-y=5` (d) none of these

Options

A. x+y+5=0
B. x-y+1=0
C. x-y=5
D. none of these

Answer

B

Explanation

Clearly, from the figure, the origin is contained in the acute angle. Writing the equations of thel lines as 2x-y+4=0 and -x+2y+1=0, the required bisector is
`(2x-y+4)/(sqrt(5)) = (-x+2y+1)/(sqrt(5))`