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If lines x+2y-1=0,a x+y+3=0, and b x-y+2...

If lines `x+2y-1=0,a x+y+3=0,` and `b x-y+2=0` are concurrent, and `S` is the curve denoting the locus of `(a , b)` , then the least distance of `S` from the origin is `5/(sqrt(57))` (b) `5//sqrt(51)` `5//sqrt(58)` (d) `5//sqrt(59)`

A

`5//sqrt(57)`

B

`5//sqrt(51)`

C

`5//sqrt(58)`

D

`5//sqrt(59)`

Text Solution

Verified by Experts

The correct Answer is:
C

The lines are concurrent if
`|{:(1,2,-1),(a,1,3),(b,-1,2):}|=0`
or 7b-3a+5=0
The locus of (a,b) is 3x-7y=5.
Least distance from (0,0) = Length of perpendicular from (0,0)
`=(5)/(sqrt(58))`
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