Consider a `DeltaABC` in which sides AB and AC are perpendicular to x-y-4=0 and 2x-y-5=0, repectively. Vertex A is (-2, 3) and the circumcenter of `DeltaABC` is (3/2, 5/2).
The equation of the line in List I is of the form ax+by+c=0, where `a,b,c in I.` Match it with the corresponding value of c in list II and then choose the correct code.

Codes :
`{:(a, b, c, d),(r, s, p, q),(s, r, q, p),(q, p, s, r),(r, p, s, q):}`

Answer

3

Explanation

a.

The perpendicular bisector of AB is parallel to x-y-4=0.
Therefore, the slope is 1.
It is passing through the circumcenter, i.e, (3/2, 5/2).
Therefore, the line is x-y+1 =0.
b. The perpendicular bisector of AC is B parallel to 2x-y-5=0.
Therefore, the slope is 2.
It is passing through the circumcenter, i.e., (3/2, 5/3).
Therefore, the line is 4x-2y-1=0.
c. The equation of perpendicular bisector to AC is 2x-y-5=0.
Therefore, the equation of AC can be `x+2y+lambda= 0.`
It is passing through A(-2, 3). Therefore,
`lambda = -4`
Therefore, the equation of AC is x+2y-4=0.
d. The image of A on the perpendicular bisector of AC is
`(x+2)/(4) = (y-3)/(-2) = (-2(-8-6-1))/(16+4) = (3)/(2)`
`therefore C-= (4, 0)`
The image of A on the perpendicular bisector of AB is
`(x+2)/(1) = (y-3)/(-1) = (-2(-2-3+1))/(1+1) = 4`
Therefore, B is (2, -1).
Therefore, the midpont of BC is D (3, -1/2).
Hence, the median through A is 7x+10y-16=0.