Home
Class 12
MATHS
The absolute value of the sum of the abs...

The absolute value of the sum of the abscissas of all the points on the line `x+y=4` that lie at a unit distance from the line `4x+3y-10=0` is___________

Text Solution

Verified by Experts

The correct Answer is:
4

Any point on the line x+y = 4 is (t, 4-4), where `t in R.`
Now, the distance of this point from the line 4x+3y-10=0 is 1. Therefore,
`(|4t +3 (4-t)-10|)/(5) = 1`
or |t+2| = 5
i.e., t = 3 or t = -7
Therefore, the sum of values is -4
Promotional Banner

Topper's Solved these Questions

  • STRAIGHT LINES

    CENGAGE|Exercise JEE Main Previous Year|9 Videos
  • STRAIGHT LINES

    CENGAGE|Exercise JEE Advanced Previous Year|4 Videos
  • STRAIGHT LINES

    CENGAGE|Exercise Exercise (Matrix)|8 Videos
  • STRAIGHT LINE

    CENGAGE|Exercise Multiple Correct Answers Type|8 Videos
  • THEORY OF EQUATIONS

    CENGAGE|Exercise JEE Advanced Previous Year|9 Videos

Similar Questions

Explore conceptually related problems

The points on the line x + y = 4 lying at a unit distance from the line 4x+3y-10=0 are

Find the points on the line x + y = 5 , that lie at a distance 2 units from the line 4x - 3y - 12 = 0 .

Find the points on the line x + y = 5 , that lie at a distance 2 units from the line 4x + 3y - 12 = 0 .

Find the points on the line x + y = 1 that lie at a distance 3 units from the line 5x+12y = 3.

Find the points on y -axis whose perpendicular distance from the line 4x-3y-12=0 is 3.

The equation of one of the lines parallel to 4x – 3y=5 and at a unit distance from the point (-1,-4) is

Find the equations of lines parallel to 3x-4y-5=0 at a unit distance from it.

What are the points on the y-axis whose distance from the line (x)/(3)+(y)/(4)=1 is 4 units.

Find the least and greatest values of the distance of the point (costheta,sintheta),theta in R , from the line 3x-4y+10=0.

The point on the line 3y - 4x + 11 = 0 equidistant from (3, 2) and (-2,3) is