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Let PS be the median of the triangle wit...

Let PS be the median of the triangle with vertices `P(2,""2),""Q(6,-1)""a n d""R(7,""3)` . The equation of the line passing through `(1,-1)` and parallel to PS is (1) `4x-7y-11""=""0` (2) `2x+""9y+""7""=""0` (3) `4x+""7y+""3""=""0` (4) `2x-9y-11""=""0`

A

4x-7y-1=0

B

2x+9y+7=0

C

4x+7y+3=0

D

2x-9y-11=0

Text Solution

Verified by Experts

The correct Answer is:
B
S is the midpoint of QR,
`therefore S((13)/(2), 1)`
Slope of PS `=-(2)/(9)`
`therefore " Equation of required line is: " y+1 = -(2)/(9)(x-1)`
`therefore 2x+9y+7=0`
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