Home
Class 12
MATHS
Find the point on the hyperbola x^2-9y^2...

Find the point on the hyperbola `x^2-9y^2=9` where the line `5x+12 y=9` touches it.

Text Solution

Verified by Experts

Solving `5x+12y=9 or y=(9-5x)/(12) and x^(2)-9y^(2)=9,` we have
`x^(2)-9((9-5x)/(12))=9`
`"or "x^(2)-(1)/(16)(9-5x)^(2)=9`
`"or "16x^(2)-(25x^(2)-90x+81)=144`
`"or "9x^(2)-(25x^(2)-90x+81)=144`
`"or "9x^(2)-90x+225=0`
`"or "x^(2)-10x+25=0`
`"or "x=5`
`rArr" "y=(9-25)/(12)=-(4)/(3)`
So, point of contact is `(5,-(4)/(3))`.
Promotional Banner

Topper's Solved these Questions

  • HYPERBOLA

    CENGAGE|Exercise Exercise 7.1|3 Videos
  • HYPERBOLA

    CENGAGE|Exercise Exercise 7.2|12 Videos
  • HIGHT AND DISTANCE

    CENGAGE|Exercise JEE Previous Year|3 Videos
  • INDEFINITE INTEGRATION

    CENGAGE|Exercise Question Bank|21 Videos

Similar Questions

Explore conceptually related problems

Find the equation of normal to the hyperbola x^2-9y^2=7 at point (4, 1).

Find the equation of normal to the hyperbola x^2-9y^2=7 at point (4, 1).

If x=9 is the chord of contact of the hyperbola x^2-y^2=9 then the equation of the corresponding pair of tangents is (A) 9x^2-8y^2+18x-9=0 (B) 9x^2-8y^2-18x+9=0 (C) 9x^2-8y^2-18x-9=0 (D) 9x^2-8y^2+18x+9=0

Tangents are drawn from any point on the hyperbola (x^2)/9-(y^2)/4=1 to the circle x^2+y^2=9 . Find the locus of the midpoint of the chord of contact.

Find the vertices of the hyperbola 9x^2-16 y^2-36 x+96 y-252=0

The vertices of the hyperbola 9x^2 - 16y^2 = 144

Find the vertices, foci for the hyperbola 9x^(2)-16y^(2)=144 .

Let P be a point on the hyperbola x^2-y^2=a^2, where a is a parameter, such that P is nearest to the line y=2xdot Find the locus of Pdot

The area of triangle formed by the tangents from the point (3, 2) to the hyperbola x^2-9y^2=9 and the chord of contact w.r.t. the point (3, 2) is_____________

Find the vertices, foci for the hyperbola 9x^(2)-16y^(2)=144.