Examine the figures and name the respective type of ovule.

Options

A. (II) (ii) (Q)
B. (III) (i) (P)
C. (I) (i) (P)
D. (I) (ii) (Q)

Answer

D

Explanation

For `a=sqrt2` and point `(-1,1)` on the curve, the only possible curve is `x^(2)+y^(2)=a^(2)`
Equation of tangent is `y=mx+asqrt(m^(2)+1)` and point of contact is `((-ma)/(sqrt(x^(2)+1)),(a)/(sqrt(m^(2)+1)))`.