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Find tan^(-1)x/(sqrt(a^2-x^2)) in terms ...

Find `tan^(-1)x/(sqrt(a^2-x^2))` in terms of `sin^(-1)` where `x in (0, a)dot`

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We have `tan^(-1) (x)/(sqrt(a^(2) - x^(2))) = theta`
From the triangle,
`tan^(-1) (x)/(sqrt(a^(2) - x^(2))) = sin^(-1) (x)/(a)`
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