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The value of (alpha^3)/2cos e c^2(1/2tan...

The value of `(alpha^3)/2cos e c^2(1/2tan^(-1)alpha/beta)+(beta^3)/2sec^2(1/2tan^(-1)(beta/alpha))i s equal to`

A

`(alpha - beta) (alpha^(2) + beta^(2))`

B

`(alpha + beta) (alpha^(2) - beta^(2))`

C

`(alpha + beta) (alpha^(2) + beta^(2))`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
C

`(alpha^(3))/(2) cosec^(2) ((1)/(2) tan^(-1). (alpha)/(beta)) + (beta^(3))/(2) sec^(2) ((1)/(2) tan^(-1).(beta)/(alpha))`
`= alpha^(3) (1)/(1 - cos(tan^(-1) ((alpha)/(beta)))) + beta^(3) (1)/(1 + cos (tan^(-1).(beta)/(alpha)))`
`= alpha^(3) (1)/(1 -cos (cos^(-1) ((beta)/(sqrt(alpha^(2) + beta^(2)))))) + beta^(3) (1)/(1 + cos (cos^(-1).(alpha)/(sqrt(alpha^(2) + beta^(2)))))`
`= alpha^(3) (1)/(1 - (beta)/(sqrt(alpha^(2) + beta^(2)))) + beta^(3) (1)/(1 + (alpha)/(sqrt(alpha^(2) + beta^(2))))`
`= sqrt(alpha^(2) + beta^(2)) ((alpha^(3))/(sqrt(alpha^(2) + beta^(2)) - beta) + (beta^(3))/(sqrt(alpha^(2) + beta^(2)) + alpha))`
`= sqrt(alpha^(2) + beta^(2)) (alpha^(3) (sqrt(alpha^(2) + beta^(2)) + beta)/(alpha^(2)) + beta^(3) (sqrt(alpha^(2) + beta^(2)) - alpha)/(beta^(2)))`
`= sqrt(alpha^(2) + beta^(2)) [alpha(sqrt(alpha^(2) + beta^(2)) + beta) + beta (sqrt(alpha^(2) + beta^(2)) - alpha)]`
`= sqrt(alpha^(2) + beta^(2)) (alpha + beta) sqrt(alpha^(2) + beta^(2))`
`= (alpha + beta) (alpha^(2) + beta^(2))`
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