solve `sin^(-1) x le cos^(-1) x`

Options

A. 1
B. 2
C. 3
D. 4

Answer

C

Explanation

`a = 20 - 6pi, b = 10 pi - 30, c = sin^(-1) sin(4pi - 10) = 10 - 3pi`
So, `a + b + c = pi`
`sin^(-1) sin x ge |x -pi| rArr x in [(pi)/(2), pi]`
So, largest integer x = 3