Match the List-I and List-II using the correct code given below the list.

Options

A. `{:(a,b,c,d),(s,r,p,q):}`
B. `{:(a,b,c,d),(q,s,r,p):}`
C. `{:(a,b,c,d),(s,r,p,q):}`
D. `{:(a,b,c,d),(q,s,p,r):}`

Answer

A

Explanation

`tan^(-1) ((1)/(2x + 1)) + tan^(-1) ((1)/(4x + 1)) = tan^(-1).(2)/(x^(2))`
`rArr tan^(-1) ((3x + 1)/(4x^(2) + 3x)) = tan^(-1).(2)/(x^(2))`
`rArr 3x^(2) - 7x -6 = 0`
`rArr x = -(2)/(3) , 3`
But for `x -(2)/(3)`, L.H.S is negative and R.H.S. is positive
Hence, the only solution is `x = 3`
Note : Solution of the remaining parts are given in their respective chapters