Find the ratio in which the line segment joining the points `A(3,8) and B(-9, 3)` is divided by the `Y-axis.

Explanation

`P_1` is midpoint of `A_1A_2`.
`therefore" "P_1-=((x_1+x_2)/(2),(y_1+y_2)/(2))`
`P_2` divides `P_1A_3` in `1:2`.
`therefore" "P_2-=((2((x_1+x_2)/2)+x_3)/(2+1),(2((y_1+y_2)/2)+y_3)/(2+1))`
`-=((x_1+x_2+x_3)/(3),(y_1+y_2+y_3)/(3))`
Now, `P_3` divides `P_2A_4` in ` 1:3`
`therefore" "P_3-=((3.((x_1+x_2+x_3)/3)+x_4)/(3+1),(3.((y_1+y_2+y_3)/3)+y_4)/(3+1))`
`-=((x_1+x_2+x_3+x_4)/(4),(y_1+y_2+y_3+y_4)/(4))`
Proceeding in this manner, we get
`P_n-=((x_1+x_2+x_3+....x_n)/(n),(y_1+y_2+y_3+....y_n)/(n))`.