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If vertex A of triangle ABC is (3,5) an...

If vertex A of triangle ABC is `(3,5)` and centroid is `(-1,2)`, then find the midpoint of side BC.

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Let midpoint of side BC be D.
So, AD is median and centroid `G(-1,2)` lies on it such that `AG:GD=2:1` .
Thus,D divides AG externally in the ratio`3:1` .
`therefore D-=((3(-1)-1(3))/(3-1),(3(2)-1(5))/(3-1))-=(-3,(1)/(2))`
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