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The incentre of the triangle with vertic...

The incentre of the triangle with vertices (1, `sqrt3`) (0,0) (2,0) is

Text Solution

Verified by Experts

The correct Answer is:
`(1,(1)/(sqrt3))`
Here `AB=BC=CA=2`
So, it is an equilateral triangle and the incentre coincides with centroid.
Therefore, centroid
`((0+1+2)/(3),(0+0+sqrt3)/(3))-=(1,(1)/sqrt3)`
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