Home
Class 12
MATHS
Find the angle between the line joining ...

Find the angle between the line joining the points `(1,-2),(3,2)` and the line `x+2y-7=0.`

Text Solution

Verified by Experts

The correct Answer is:
`pi//2`
`x+2y-7=0`
Slope of line (i) `m_1=(1)/(2)`
Slope of line `PQ=m_2=(2-(-2))/(3-1)=2`
where `P-=(1,-2)` and `Q-=(3,2)`.
Since `m_1,m_2=-1` the angle between line (1) and line `PQ is pi//` .
Promotional Banner

Topper's Solved these Questions

  • COORDINATE SYSYEM

    CENGAGE|Exercise Exercise 1.5|5 Videos

  • COORDINATE SYSYEM

    CENGAGE|Exercise Exercise 1.6|9 Videos

  • COORDINATE SYSYEM

    CENGAGE|Exercise Exercise 1.3|10 Videos

  • COORDINATE SYSTEM

    CENGAGE|Exercise Multiple Correct Answers Type|2 Videos

  • CROSS PRODUCTS

    CENGAGE|Exercise DPP 2.2|13 Videos

Similar Questions

Explore conceptually related problems

The angle between the line joining the points (1,-2) , (3,2) and the line x+2y -7 =0 is

Find the angle between x-axis and the line joining (2,-1) and (4, -3).

Find the slope of a line joining the given points (-6,1) and (-3,2)

. Find the angle between the x-axis and the line joining the points (3, -1) " and " (4, -2) .

The equation of the line joining the points (-3,4,11) and (1,-2,7) is

Find the angle between the lines 3x^(2)-10xy-3y^(2)=0 :

The angle between the lines joining origin to the points of intersection of the line sqrt(3)x+y=2 and the curve y^2-x^2=4 is (A) tan^(-1)(2/(sqrt(3))) (B) pi/6 (C) tan^(-1)((sqrt(3))/2) (D) pi/2

Find the vector and cartesian equation of the line joining the points (1, -2, 1) and (0, -2, 3).