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Convert 2x^2+3y^2=6 into the polar equat...

Convert `2x^2+3y^2=6` into the polar equation.

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The correct Answer is:
`r^2(2+sin^2theta)=6`
`2x^2+3y^2=6`
or `2(rcostheta)^2+3(rsintheta)^2=6`
or `2r^2cos^2theta+3r^2sin^2theta=6`
or `2r^2+r^2sin^2theta=6`
or `r^2(2+sin^2theta)=6`
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