Point `A` and `B` are in the first quadrant; point `O` is the origin. If the slope of `O A` is 1, the slope of OB is 7, and `O A=O B ,` then the slope of `A B` is `a.-1/5` (b) `-1/4` (c) `-1/3` (d) `-1/2`

Options

A. `-1//5`
B. `-1//4`
C. `-1//3`
D. `-1//2`

Answer

D

Explanation

`tantheta=7`
` OA=OB=r`
`sintheta=(7)/(5sqrt2)costheta=(1)/(5sqrt2)`
Now, `m_(AB)=1//2`.