The locus of a point reprersented by `x=a/2((t+1)/t),y=a/2((t-1)/1)` , where `t in R-{0},` is `x^2+y^2=a^2` (b) `x^2-y^2=a^2` `x+y=a` (d) `x-y=a`

Options

A. `x^2+y^2=a^2`
B. `x^2-y^2=a^2`
C. `x+y=a`
D. `x-y=a`

Answer

C

Explanation

Here,
`x=(a)/(2)(2+(1)/(t))` .....(1)
`y=(a)/(2)(1-(1)/(t))`......(2)
Adding (i) and (ii) we get `x+y=a`
which is the required locus.