Evaluate `int (x-1)/(x+1) dx`

Answer

B

Explanation

`OP le "min"[BP,AP]`
`OP le AP(whenAPlt BP)`
Let `OP=BP`. The P lies on the perpendicular bisector of OB, For `OP=AP,P` lies on the perpendiuclar bisector of OA. Then, for the required condition, P lies in the region as shown in the diagram. the area of region `OMPN` is
`(1)/(2)xx|{:(0,,0,,),(1,,0,,),(1,,1//sqrt3,,),(1/2,,sqrt(3)//2,,),(0,,0,,):}|=(1)/(2)[(1)/(sqrt3)+(sqrt3)/(2)-(1)/(2sqrt3)]`
`=(1)/(2)[sqrt(3)/(2)+(1)/(sqrt3)]=(1)/(sqrt3)`