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Let ABCD be a square with sides of unit ...

Let ABCD be a square with sides of unit lenght. Points E and F are taken on sides AB and AD, respectively,so that `AE=AF`. Let P be a point inside the squre ABCD.
The value of `(PA)^2-(PB)^2+(PC)^2-(PD)^2` is equal to

A

3

B

2

C

1

D

0

Text Solution

Verified by Experts

The correct Answer is:
D

`(PA)^2-(PB)^2+(PC)^2-(PD)^2`
`=(alpha^2+gamma ^2)-(alpha^2+delta^2)+(delta^2+beta^2)-(gamma^2+beta^2)=0`
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