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In ΔABC, then show that r(r1+r2+r3)=ab+b...

In `ΔABC`, then show that `r(r_1+r_2+r_3)=ab+bc+ac−s^2`.

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The correct Answer is:
D

In a triangle orthocenter A centriod B and circumcentre C are always collinear such that `AB:BC=2:1`

So, slope of AD is infinity.
Let orthocenter have coordinates (2,k).
Slope of AC is `-2`.
`therefore Slope of BH,(k-2)/(2-5)=(1)/(2)`
`therefore k=(1)/(2)`
`therefore AC=sqrt((6-(-3))^2+(2-5)^2)=sqrt(81+9)=sqrt90=3sqrt10`
AC is diameter of the circle.
`therefore`"Radius of circle" `=(3)/(2)sqrt10=3sqrt(5/(2))`
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