Home
Class 12
MATHS
If the constant term in the binomial exp...

If the constant term in the binomial expansion of `(x^2-1/x)^n ,n in N` is 15, then the value of `n` is equal to.

Text Solution

Verified by Experts

The correct Answer is:
6

`T_(r+1) = .^(n)C_(r)(x^(2))^(n-r)(-1)^(r ) x^(-r)`
`= .^(n)C_(r) x^(2n-3r)(-1)^(r)`
Constant term `= .^(n)C_(r)(-1)^(r)` if `2n = 3r`
i.e, coefficient of `x = 0`
Hence, `.^(n)C_(2pi//3)(-1)^(2n//3) = 15 = .^(6)C_(4)`
Promotional Banner

Topper's Solved these Questions

  • BINOMIAL THEOREM

    CENGAGE|Exercise JEE Previous Year|16 Videos
  • BINOMIAL THEOREM

    CENGAGE|Exercise Single correct Answer|62 Videos
  • BINOMIAL THEOREM

    CENGAGE|Exercise Matrix|4 Videos
  • AREA UNDER CURVES

    CENGAGE|Exercise Question Bank|10 Videos
  • CIRCLE

    CENGAGE|Exercise MATRIX MATCH TYPE|6 Videos

Similar Questions

Explore conceptually related problems

If the middle term in the expansion of (x^2+1//x)^n is 924 x^6, then find the value of ndot

The number of real negative terms in the binomial expansion of (1+i x)^(4n-2),n in N ,x >0 is

If the three consecutive coefficients in the expansion of (1+x)^n are 28, 56, and 70, then the value of n is.

Find the r^th term from the end in the expansion of (x + a)^n .

If the 2nd, 3rd and 4th terms in the binomial expansion of (x+a)^(n) are 240, 720 and 1080 for a suitable values of x, find x, a and n.

In the binomial expansion of (a - b)^(n) , n gt= 5 , the sum of 5^(th) and 6^(th) term a/b equals

If the binomial coefficients of three consecutive terms in the expansion of (a+x)^n are in the ratio 1:7 :42 , then find n .

If a,b,c,d be four consecutive coefficients in the binomial expansion of (1+x)^(n) , then value of the expression (((b)/(b+c))^(2)-(ac)/((a+b)(c+d))) (where x gt 0 and n in N ) is

If the 4th term in the expansion of (a x+1//x)^n is 5/2, then (a) a=1/2 b. n=8 c. a=2/3 d. n=6

The 2^(nd), 3^(rd) and 4^(th) terms in the binomial expansion of (x+a)^(n) are 240, 720 and 1080 for a suitable value of x. Find x, a and n.

CENGAGE-BINOMIAL THEOREM-Exercise (Numerical)
  1. Least positive integer just greater than (1+0. 00002)^(50000) is.

    Text Solution

    |

  2. If the second term of the expansion [a^(1/(13))+a/(sqrt(a^(-1)))]^n is...

    Text Solution

    |

  3. If the constant term in the binomial expansion of (x^2-1/x)^n ,n in N...

    Text Solution

    |

  4. The largest value of x for which the fourth tem in the expansion (5^2/...

    Text Solution

    |

  5. Let a and b be the coefficients of x^3 in (1+x+2x^2+3x^3)^4a n d(1+x+2...

    Text Solution

    |

  6. If R is remainder when 6^(83)+8^(83) is divided by 49, then the value ...

    Text Solution

    |

  7. The remainder, if 1+2+2^2++2^(1999) is divided by 5 is.

    Text Solution

    |

  8. Given (1-2x+5x^2-10 x^3)(1+x)^n=1+a1x+a2x^2+ and thata1 2=2a2 then the...

    Text Solution

    |

  9. The largest real value of x such that sum(k=0)^4((3^(4-k))/((4-k)!))((...

    Text Solution

    |

  10. Coefficient of x^(2009) in (1+x+x^(2)+x^(3)+x^(4))^(1001) (1-x)^(1002)...

    Text Solution

    |

  11. The total number of different terms in the product (.^(101)C(0) - .^(1...

    Text Solution

    |

  12. The constant term in the expansion of (x -2/x^(2))^(9) is

    Text Solution

    |

  13. The value of sum(r=0)^(3) ""^(8)C(r)(""^(5)C(r+1)-""^(4)C(r)) is "".

    Text Solution

    |

  14. The value of (.^(21)C(1) - .^(10)C(1)) + (.^(21)C(2) - .^(10)C(2)) + (...

    Text Solution

    |

  15. Let a=3^(1/(223))+1 and for all geq3,let f(n)=^n C0dota^(n-1)-^n C1do...

    Text Solution

    |

  16. Let 1+sum(r=1)^(10)(3^rdot(10)Cr+rdot(10)Cr)=2^(10)(alpha. 4^5+beta)w ...

    Text Solution

    |

  17. The value of (lim)(nvecoo)sum(r=1)^(r-1)(sum(t=0)^(r-1)1/(5^n)dot^n Cr...

    Text Solution

    |

  18. If sum(r=0)^(10)((r+2)/(r+1))^^n Cr=(2^8-1)/6 , then n is 8 b. 4 c. 6 ...

    Text Solution

    |

  19. If S(n) = (.^(n)C(0))^(2) + (.^(n)C(1))^(2) + (.^(n)C(n))^(n), then ma...

    Text Solution

    |

  20. The value of .^(40)C(0) xx .^(100)C(40) - .^(40)C(1) xx .^(99)C(40) + ...

    Text Solution

    |