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If x=m x+c touches the parabola y^2=4a(x...

If `x=m x+c` touches the parabola `y^2=4a(x+a),` then `c=a/m` (b) `c=a m+a/m` `c=a+a/m` (d) none of these

A

`c=(1)/(m)`

B

`c=am+(a)/(m)`

C

`c=a+(a)/(m)`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B
(2) The equation of tangent to the given parabola having slope m is
`y=m(x+a)+(a)/(m)`
`ory=mx+am+(a)/(m)`
Comparing (1) with y=mx+c, we have
`c=am+(a)/(m)`
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