`y=x+2` is any tangent to the parabola `y^2=8xdot` The point `P` on this tangent is such that the other tangent from it which is perpendicular to it is (a)`(2,4)` (b) `(-2,0)` (c)`(-1,1)` (d) `(2,0)`

Options

A. (2,4)
B. (-2,0)
C. (-1,1)
D. (2,0)

Answer

B

Explanation

(2) Clearly, P is the point of intersection of two perpendicular tangents to the parabola `y^(2)=8x`.
Hence, P must lie on the directrix x+a=0orx+2=0.
Therefore, x=-2.
Hence, the point is (-2,0).