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Show that |veca|vecb+|vecb|veca is perp...

Show that `|veca|vecb+|vecb|veca` is perpendicular to `|veca|vecb-|vecb|veca`, for any two nonzero vectors `vecaandvecb`.

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`(|veca|vecb+ |vecb|veca).(|veca|vecb- |vecb|veca)`
=`|veca|^(2)vecb.vecb- |veca||vecb|^(2)vecb.veca`
`+ |vecb||veca|veca.vecb-|veca||vecb|^(2)veca.veca`
`= |veca|^(2)|vecb|^(2)-|vecb|^(2)|veca|^(2)`
=0
Hence, `|veca|vecb + |vecb|veca and |veca|vecb- |vecb|veca` are perpendicular to each other .
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CENGAGE-DIFFERENT PRODUCTS OF VECTORS AND THEIR GEOMETRICAL APPLICATIONS -Exercise
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  15. If veca and vecb are unit vectors, then find the greatest value of |ve...

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  17. Find |veca|and|vecb|, if (veca+vecb)*(veca-vecb)=8and|veca|=8|vecb|.

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