Show that `(veca-vecb)xx(veca+vecb)=2(vecaxxvecb)`

Explanation

`(veca - vecb) xx (veca + vecb) `
`= vecaxxveca + vecaxxvecb -vecbxxveca -vecbxxvecb`
`= veca xx veca + veca xx vecb + veca xx vecb -vecb xx vecb`
`= vec0 + 2veca xx vecb - vec0 = 2vea xx vecb`
Geometrically, the vector area of a parallelogram, whose sides are along vectors, `veca and vecb is veca xx vecb`. Also diagonals are long vectors, `veca - vecb and veca + vecb` and the vector area in terms of diagonal vectors is
`1/2 [(veca -vecb) xx (veca + vecb)]`