If veca= hati +hatj, vecb= hatj + hatk, ...

If `veca= hati +hatj, vecb= hatj + hatk, vecc = hatk + hati ` then in the reciprocal system of vectors `veca, vecb, vecc` reciprocal `veca` of vector `veca` is

`(hati + hatj + hatk)/2`

`(hati - hatj + hatk)/2`

`(-hati - hatj + hatk)/2`

`(hati + hatj - hatk)/2`

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The correct Answer is:

`veca' = (vecb xx vecc) / ([veca vecb vecc] ) = (hati + hatj - hatk) / 2`

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