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If veca=hati+hatj+hatk, veca.vecb=1 and ...

If `veca=hati+hatj+hatk, veca.vecb=1` and `veca xx vecb = hati-hatk`, then `vecb.(3hati+4hatj+5hatk) =`

A

`hati - hatj + hatk`

B

`2hati - hatk`

C

`hati`

D

`2hati`

Text Solution

Verified by Experts

The correct Answer is:
c

`(veca xx vecb) xxveca = (veca.veca)vecb- (veca.vecb)veca`
`(hatj-hatk)xx (hati +hatj +hatk) = (sqrt3)^(2)vecb - (hati +hatj +hatk)`
`or 3vecb = 3hati or vecb = hati`
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