Draw the graph of `y=log_e(−x)`, flip the graph of `y=log_e x` over the y-axis

Answer

`a to r ;b to s ; c to p ; d to q`

Explanation

` [veca vecb vecc] =2 `
`Rightarrow[2veca xx vecb " " 3vecb xx vecc " "veccxxveca]^(2)= 6xx 4 =24 `
b. `[ veca vecb vecc ] =5 `
`Rightarrow[3 (veca + vecb)vecb+vecc2(vecc+veca)]`
`6[(veca +vecb)vecb +vecc(vecc + veca)] = 12 [vecavecb vecc]=60`
c. Given ` 1/2 |veca xx vecb | =20`
`1/2|(2veca+3vecb) xx (veca -vecb)|`
`5/2 xx 40 = 100`
d. Given ` |veca xx vecb|=30 Rightarrow |veca + vecb) xx veca |=|vecb xx veca|=30`