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Find (dy)/(dx)fory=xsinxlogxdot...

Find `(dy)/(dx)fory=xsinxlogxdot`

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We have
`(d)/(dx) (x sin x log x)`
`={(d)/(dx)(x)}sin x log x+x{(d)/(dx)(sin x)} log x + x sin x{(d)/(dx) (log x)}`
`=1xxsinxxlog x + x xx cos x xx log x + x xx sin x xx(1)/(x)`
`=sin x log x + x cos x log x + sin x`
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